In an examination hall, students are seated at a distance of 2 m from each other, to maintain the social distance due to CORONA virus pandemic. Let three students sit at points A, B and C whose coordinates are (4, -3), (7, 3), and (8, 5) respectively. Based on the above information, answer the question
The distance between A and C is

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Solution

The distance between A(4, - 3) and C(8, 5) can be calculated using distance formula.
And distance between the points is given by
$\sqrt{{(x_{1} - x_{2})}_{1}^{2} + {(y_{1} - y_{2})}_{1}^{2}}$
Therefore, $\sqrt{(8 - 4)^{2} + (5 - (- 3))^{2}}$
$\sqrt{(4)^{2} + (8)^{2}} =$ $\sqrt{16 + 64} = \sqrt{80} = 4 \sqrt{5}$

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The distance between A(4, - 3) and C(8, 5) can be calculated using distance formula. And distance between the points is given by √(x1−x2)2+(y1−y2)2 Therefore, √(8−4)2+(5−(−3))2 √(4)2+(8)2=√16+64=√80=4√5