Question

In an examination in which full marks were $500$. $A$ got $25$% more than $C$, $C$ got $20$% less than $D$. If $A$ got $360$ marks. What percentage of full marks was obtained by $D$?

• A. $72$%
• B. $80$%
• C. $50$%
• D. $60$%

Answer 1

The correct option is A $72$%

given,full marks in the examination are $500$

A got $360$ marks

A got $25\%$ more than $C$.

let the marks of $C$ be ${}^{\prime }{x}^{\prime }$ then,

$x+\frac{25}{100}\times x=360$

$\frac{5x}{4}=360$

$x=288$

so,$C$ got $288$ marks .

given,$C$ got $20\%$ less than $D$ let the marks of $D$ be ${}^{\prime }{y}^{\prime }$ then,

$y-\frac{20}{100}\times y=288$

$\frac{4y}{5}=288$

$y=360$

so,$D$ got $360$ marks percentage of full marks obtained by $D$ $=\frac{360}{500}\times 100$

$=72\%$