Question

In an examination, the pass percentage is $33\%$. A candidate secured $310$ marks and failed by $53$ marks. What is the maximum mark?

Answer 1

Let $x$ be the maximum marks.

$\therefore$ Passing marks $=\frac{33}{100}\times x=\frac{33x}{100}$

Now, according to the question-

$\frac{33x}{100}-53=310$

$\Rightarrow \frac{33x}{100}=310+53$

$\Rightarrow x=\frac{36300}{33}=1100$

Hence the maximum marks are $1100$.