Question

In an examination, there are three papers each of 100 marks. A candidate obtained 53 marks in the first paper and 75 marks in the second paper. How many marks must the candidate obtain in the third paper to get an overall of 70% marks?

Answer 1

Let x be the marks of the candidate in the third paper.
Then, total marks secured in all throe papers = 53 + 75 + x
Total marks of three papers = 100 + 100 + 100 = 300
$\therefore Percentageofmaks=\left(\frac{Totalmarkssecured}{Totalmarks}\right)\times 100\%=\frac{53+75+x}{300}\times 100\%$
But it is given that, he obtained overall of 70% marks.
$\therefore \frac{53+75+x}{300}\times 100=70\Rightarrow \frac{128+x}{3}=70\Rightarrow 128+x=210\Rightarrow x=210-128\therefore x=82$
Hence, he must secure 82 marks in the third paper to get an overall of 70 % marks.