In an experiment, $0.04 F$ was passed through $400 m L$ of a $1 M$ solution of $N a C l$ . What would be the $p H$ of the solution after the electrolysis?

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Solution

The correct option is D $13$
Electrolysis of $a q . N a C l$ gives hydrogen gas at cathode and oxygen gas at anode, the electrolyte solution contains $N a O H$ after electrolysis.
Number of equivalents of $N a O H$ formed $= 0.04$
Normality, $N = \frac{0.04 \times 1000}{400} = 0.1$
$[O H^{-}] = 0.1 M$
$p O H = 1 ∴ p H = 13$ .

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In an experiment, 0.04 F was passed through 400 mL of a 1 M solution of NaCl. What would be the pH of the solution after the electrolysis?

The correct option is D 13Electrolysis of aq.NaCl gives hydrogen gas at cathode and oxygen gas at anode, the electrolyte solution contains NaOH after electrolysis.Number of equivalents of NaOH formed =0.04Normality, N=0.04×1000400=0.1[OH−]=0.1 MpOH=1∴pH=13.

In an experiment, $0.04 F$ was passed through $400 m L$ of a $1 M$ solution of $N a C l$ . What would be the $p H$ of the solution after the electrolysis?