In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34∘C to its freezing temperature. The specific heat capacity of water is 4.2 J g−1 K−1. Calculate the specific latent heat of ice. State one important assumption made in the above calculation.
Heat lost by water at 34oC to convert to water at 0oC = 40×4.2×34=5712 J
Heat required to melt 17 g of ice = 17×L
Now, 17×L=5712
∴L=336 J/g
Here, we have assumed that there is no loss of energy.