Find the result of mixing 10 g of ice at - $10^{\circ} C$ with 10 g of water at $10^{\circ} C$ .Specific heat capacity of ice=2.1 J $g^{- 1} K^{- 1}$ ,specific latent heat of ice=336 J $g^{- 1}$ and specifc heat capacity of water =4.2 J $g^{- 1} K^{- 1}$ .

Q. How much heat energy is released when

5 g

of water at

20^{o} C

changes to ice at

0^{o} C

?
[Specific heat capacity of water

= 4.2 J g^{- 1} C^{- 1}

.
Specific latent heat of fusion of ice

= 336 J g^{- 1}

]

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In an experiment, 17 g of ice is used to bring down the temperature of 40 g of water at 34oC to its freezing temperature. The specific heat capacity of water is 4.2 J g−1 K−1. Calculate the specific latent heat of ice :

The correct option is C 336 J g−1heat lost by water = heat gain by ice40×4.2×34=17×LL=336 Jg−1

In an experiment, $17$ g of ice is used to bring down the temperature of $40$ g of water at $34$ $^{o}$ C to its freezing temperature. The specific heat capacity of water is $4.2$ J g $^{- 1}$ K $^{- 1}$ . Calculate the specific latent heat of ice :

The correct option is C 336 J g $^{- 1}$
heat lost by water = heat gain by ice
$40 \times 4.2 \times 34 = 17 \times L$
L=336 $J g^{- 1}$