You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Arrhenius Acid

In an experim...

Question

In an experiment, $20 m L$ of decinormal $H C l$ solution was added to $10 m L$ of a decinormal $A g N O_{3}$ solution. $A g C l$ was precipitated out and the excess acid was titrated against a decinormal $N a O H$ solution. Volume of $N a O H$ required for this back titration is:

10 m L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $10 m L$
$10 m L 0.1 N A g N O_{3}$ will react with $10 m L$ of $0.1 N H C l$ .
$∴ 0.1 N H C l l e f t = 10 m L$
Thus, it will neutralise $10 m L$ of $0.1 N N a O H$ .

Suggest Corrections

Similar questions

12.5 m L

of a solution containing

6 g

of a dibasic acid in

1 L

was found to be neutralized by

10 m L

of a decinormal solution of

N a O H

. The molecular mass of the acid is:

Q. A 20 ml solution of 0.1 N

N a_{2} C O_{3}

is titrated with 0.1N HCl with phenolphthalein as the indicator. Another 20 ml solution of 0.1 N

N a_{2} C O_{3}

is titrated with 0.1 N HCl with methyl orange as the indicator. The volume of HCl required for both the titrations resepectively is:

Q. A

100

ml solution of

0.1 N H C l

was titrated with

0.2

N a O H

solution. The titration was discontinued after adding

30 m l

N a O H

solution. The remaining solution was titrated with

0.25 N K O H

solution. The volume of

K O H

required to complete the titration is:

Q. A solution of weak acid

H A

was titrated with base

N a O H

. The equivalence point was reached when

36.12 m L

0.1 M

N a O H

has been added. Now

18.06 m L

0.1 M

H C l

were added to titrated solution, the

p H

was found to be

4.92

. What will be the

p H

of the solution obtained by mixing

10 m L

0.2 M

N a O H

and

10 m L

0.2 M

H A

A 100ml solution of 0.1N HCl was titrated with 0.2N NaOH solution . The titration was discontinued after adding 30ml of NaOH solution . The remaining titration was completed by adding 0.25 N KOH solution . The volume of KOH required for completing the titration is ___ .

(a) 70 ml. (b) 32 ml. (c)35 ml. (d)16ml

Join BYJU'S Learning Program

In an experiment, 20 mL of decinormal HCl solution was added to 10 mL of a decinormal AgNO3 solution. AgCl was precipitated out and the excess acid was titrated against a decinormal NaOH solution. Volume of NaOH required for this back titration is:

The correct option is C 10 mL10 mL 0.1 N AgNO3 will react with 10 mL of 0.1 N HCl.∴0.1 N HCl left=10 mLThus, it will neutralise 10 mL of 0.1 N NaOH.

In an experiment, $20 m L$ of decinormal $H C l$ solution was added to $10 m L$ of a decinormal $A g N O_{3}$ solution. $A g C l$ was precipitated out and the excess acid was titrated against a decinormal $N a O H$ solution. Volume of $N a O H$ required for this back titration is:

The correct option is C $10 m L$
$10 m L 0.1 N A g N O_{3}$ will react with $10 m L$ of $0.1 N H C l$ .
$∴ 0.1 N H C l l e f t = 10 m L$
Thus, it will neutralise $10 m L$ of $0.1 N N a O H$ .