In an experiment, 20mL of decinormal HCl solution was added to 10mL of a decinormal AgNO3 solution. AgCl was precipitated out and the excess acid was titrated against a decinormal NaOH solution. Volume of NaOH required for this back titration is:
A
10mL
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B
5mL
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C
20mL
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D
30mL
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Solution
The correct option is C10mL 10mL0.1NAgNO3 will react with 10mL of 0.1NHCl. ∴0.1NHClleft=10mL Thus, it will neutralise 10mL of 0.1NNaOH.