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Question

In an experiment, 20 mL of decinormal HCl solution was added to 10 mL of a decinormal AgNO3 solution. AgCl was precipitated out and the excess acid was titrated against a decinormal NaOH solution. Volume of NaOH required for this back titration is:

A
10 mL
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B
5 mL
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C
20 mL
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D
30 mL
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Solution

The correct option is C 10 mL
10 mL 0.1 N AgNO3 will react with 10 mL of 0.1 N HCl.
0.1 N HCl left=10 mL
Thus, it will neutralise 10 mL of 0.1 N NaOH.

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