In an experiment 3g of hydrogen was obtained. If hydrogen and oxygen combine in the ratio of 1: 8. Prove the law of constant proportion.

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Solution

$1 g$ of hydrogen gas $= 8 g$ of oxygen gas
So, $3 g$ of hydrogen gas requires $= 8 \times 3 g$ of oxygen gas $= 24 g$ of oxygen gas. It is governed by the law of constant proportions.The Law of constant proportion states that a chemical compound always contains exactly the same proportion of elements by mass.

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In an experiment 3g of hydrogen was obtained. If hydrogen and oxygen combine in the ratio of 1: 8. Prove the law of constant proportion.

1 g of hydrogen gas =8 g of oxygen gasSo, 3 g of hydrogen gas requires =8×3 g of oxygen gas =24 g of oxygen gas. It is governed by the law of constant proportions.The Law of constant proportion states that a chemical compound always contains exactly the same proportion of elements by mass.