wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In an experiment 4 gm of M2Ox oxide is reduced to 2.8 gm of metal. If the atomic wt Of metal is 56 gm/mol. Find the number of oxygen atoms in the oxide.

A
1.513×1022
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.413×1031
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.413×1029
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.513×1032
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1.513×1022
As M2Ox gives =2M(56×2+16x)g112g 4 g of M2Ox(112112+16x)×4 g metal
M2Ox reduces to 2.8 g of metal Hence, 112×4112+16x=2.8x=3
x=3 So, oxide is M2O3 . Mass of Oxygen in M2O3=42.8 Total atoms of Oxygen =1.23×16×6.023×1023=1.5×1022 atoms

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Oxidising and Reducing Agent
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon