Question

In an experiment for determination of refractive index of glass of a prism by $i-\delta$ plot, it was found that a ray incident at angle ${35}^{\circ }$ suffers a deviation of ${40}^{\circ }$ and that it emerges at angle ${79}^{\circ }.$ In that case, which of the following is closest to the maximum possible value of the refractive index?

• A. 1.6
• B. 1.7
• C. 1.8
• D. 1.5

Answer 1

The correct option is D 1.5

$i={35}^0,\delta ={40}^0,e={79}^0$
$\delta =i+e-A$
$A={74}^o$
$\because \delta \le {40}^o$
${\mu }_{max}=\frac{\sin \left(\frac{74+40}{2}\right)}{\sin 37}$
${\mu }_{max}=1.44$