In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10⁻¹⁵ V s. Calculate the value of Planck’s constant.

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Solution

The slope of the cut-off voltage (V) versus frequency (ν) of an incident light is given as:

Where,

e = Charge on an electron = 1.6 × 10⁻¹⁹ C

h = Planck’s constant

Therefore, the value of Planck’s constant is

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In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10−15 V s. Calculate the value of Planck’s constant.

The slope of the cut-off voltage (V) versus frequency (ν) of an incident light is given as: Where, e = Charge on an electron = 1.6 × 10−19 C h = Planck’s constant Therefore, the value of Planck’s constant is

In an experiment on photoelectric effect, the slope of the cut-off voltage versus frequency of incident light is found to be 4.12 × 10⁻¹⁵ V s. Calculate the value of Planck’s constant.

The slope of the cut-off voltage (V) versus frequency (ν) of an incident light is given as:

Where,

e = Charge on an electron = 1.6 × 10⁻¹⁹ C

h = Planck’s constant

Therefore, the value of Planck’s constant is