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Standard XII

Physics

Two Parallel Currents

In an experim...

Question

In an experiment, setup $A$ consists of two parallel wires which carry currents in opposite directions as shown in the figure. $A$ second setup $B$ is identical to setup $A$ , except that there is a metal plate between the wires.
Let $F_{A}$ and $F_{B}$ be the magnitude of the force between the two wires in setup $A$ and $B$ , respectively, then which of the following condition is correct:

F_{A} > F_{B} \neq 0

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F_{A} < F_{B}

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F_{A} = F_{B} \neq 0

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F_{A} > F_{B} = 0

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Solution

The correct option is C $F_{A} = F_{B} \neq 0$
Placing a metal plate between the wires in setup $B$ does not affect the magnetic force exerted between the wires since,
$F = \frac{μ_{0}}{2 π} - \frac{I_{1} I_{2}}{r^{2}}$
is independent of dielectric constant (which changes due to metal sheet.)

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The correct option is C FA=FB≠0Placing a metal plate between the wires in setup B does not affect the magnetic force exerted between the wires since,F=μ02π−I1I2r2is independent of dielectric constant (which changes due to metal sheet.)

The correct option is C $F_{A} = F_{B} \neq 0$
Placing a metal plate between the wires in setup $B$ does not affect the magnetic force exerted between the wires since,
$F = \frac{μ_{0}}{2 π} - \frac{I_{1} I_{2}}{r^{2}}$
is independent of dielectric constant (which changes due to metal sheet.)