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Question

In an experiment, the refractive index of glass was observed to be 1.45,1.56,1.54,1.44,1.54 and 1.53. Calculate Mean absolute error.

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Solution

Mean value of measurements =n=Sumofallmeasurements6=1.51

Absolute error of each measurement = | measurement - mean value |

=0.06,0.05,0.03,0.07,0.03,0.02 (only absolute value)

Mean value of Absolute error =Δn=0.043 (arithmatic mean of above )


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