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Question

# In an experiment, the values of refractive indices of glass were found to be 1.54, 1.53, 1.44, 1.54,1.56 and 1.45 in successive measurements. Find the following:i) Mean value of refractive index of the glass ii) Mean absolute error iii) Relative erroriv) Percentage error

A
1.51, 0.04, 0.03, 3%
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B
1.51, 3, 0.03, 0.04%
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C
3, 0.04, 1.51, 0.03%
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D
0.04, 1.51, 3, 0.03%
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Solution

## The correct option is A 1.51, 0.04, 0.03, 3%Mean=1.54+1.53+1.44+1.54+1.56+1.456 =1.51|Mean absolute error|=√16∑(¯x1−¯x)2=0.04Relative error=Absolute errorMean=0.041.51=0.026≈0.03% error= Relative error×100=3%

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