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Question

In an experiment to determine the densities, four solids A, B, C and D are immersed in a liquid contained in a measuring cylinder, one by one. The volumes of water displaced by the solids A, B, C and D are 100 cm3, 100 cm3, 80 cm3 and 80 cm3, respectively. When weighed in air, the masses of solids A, B, C, and D were found to be 80g, 100g, 100g and 80g, respectively. The two solids having identical densities are :
(1) A and C
(2) B and D
(3) C and D
(4) A and D

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Solution

Weights of the liquid displaced by A, B, C, and D are 100 g, 100 g, 80 g, and 80 g respectively, as the density of the water is 1 g/cm3. Now we can see the solid B and D displaces the liquid equal to their own weights, that means buoyant force is equal to the weight of the body in case of solids b and D. By this we can conclude that the density of both B and D is equal to the density of water, which makes their density identical, that's why they are experiencing the same buoyant force equal to their own weight.

Hence, the correct answer is option 2.

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