Question

In an experiment to find zero error of vernier caliper, it is found that zero of vernier scale is left to zero of main scale and $4^{th}$ division of vernier matches with a division on main scale. Given that 9 division of main scale is equal to 10 division of vernier and one division of main scale is 1 mm. Then zero error with sign is

• A. +0.4 mm
• B. -0.4 mm
• C. +0.6 mm
• D. -0.6 mm

Answer 1

The correct option is C +0.6 mm

$\text{zero error}=-1+4\times L\cdot C$

$1MSD=1mm$

$9MSD=10VSD$

$\text{1 VSD}=0.9\text{MSD}$

$\therefore LC=1MSD-1VSD$$=0.1mm$

$\text{zero error}=-1+4\times 0.1$$=0.6mm$