In an hydroelectric power station, the height of dam is 10 m. How many kg of water must fall per second on the blades of a turbine in order to generate 1 MW of electric power?

10^{3} k g s^{- 1}

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10^{4} k g s^{- 1}

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10^{5} k g s^{- 1}

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10^{6} k g s^{- 1}

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Solution

The correct option is A $10^{4} k g s^{- 1}$
Given that
$P = 1 M W = 10^{6} W$
h = 10 m
Let, m kg of water is falling per second on the blades of a turbine, hence
$P = m g h$
$\Rightarrow m = \frac{P}{g h}$
$m = \frac{10^{6}}{(10) (10)}$
$m = 10^{4} K g s^{- 1}$

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In an hydroelectric power station, the height of dam is 10 m. How many kg of water must fall per second on the blades of a turbine in order to generate 1 MW of electric power?

The correct option is A 104kgs−1Given thatP=1MW=106Wh = 10 mLet, m kg of water is falling per second on the blades of a turbine, henceP=mgh⇒m=Pghm=106(10)(10)m=104Kgs−1

The correct option is A $10^{4} k g s^{- 1}$
Given that
$P = 1 M W = 10^{6} W$
h = 10 m
Let, m kg of water is falling per second on the blades of a turbine, hence
$P = m g h$
$\Rightarrow m = \frac{P}{g h}$
$m = \frac{10^{6}}{(10) (10)}$
$m = 10^{4} K g s^{- 1}$