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Question

In an hydrogen atom, the electron is making 6.6×1015rps. If the radius of the orbit is 0.53×1010m, then the equivalent magnetic dipole moment is approximately

A
1029Am2
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B
1027Am2
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C
1023Am2
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D
1019Am2
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Solution

The correct option is A 1023Am2
ω=6.6×1015 rps
r=0.53×1010
Now current due to revolution of electron is
Now,ω=6.6×2π×1015
ω=4.14×1016
Now current = charge x angular velocity
I=1.6×1019×4.14×1016
i=5.35×103
Magneticmoment=NIS
M=5.35×103×π×(0.53×1010)2
M=4.72×1023
Therefore, it is almost equal to M=1023Am2
option(C)

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