In an hydrogen atom- the electron revolves around the nucleus in an orbit of radius 0-53 -10 - 10m- Then the electrical potential produced by the nucleus at the position of the electron is

V = ( Kqr) = ( 9 ×10^9× 1.6 ×10^ 190.53 ×10^ 10) #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; = 27.16 ...

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Standard XII

Physics

Electric Potential at a Point in Space Due to a Point Charge Q

In an hydroge...

Question

In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius $0.53 \times 10^{- 10} m .$ Then the electrical potential produced by the nucleus at the position of the electron is

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Solution

$V = (\frac{K q}{r}) = (\frac{9 \times 10^{9} \times 1.6 \times 10^{- 19}}{0.53 \times 10^{- 10}})$
$= 27.16 V$

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In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius 0.53×10−10m. Then the electrical potential produced by the nucleus at the position of the electron is

V=(Kqr)=(9×109×1.6×10−190.53×10−10) =27.16V

In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius $0.53 \times 10^{- 10} m .$ Then the electrical potential produced by the nucleus at the position of the electron is

$V = (\frac{K q}{r}) = (\frac{9 \times 10^{9} \times 1.6 \times 10^{- 19}}{0.53 \times 10^{- 10}})$
$= 27.16 V$