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In an ideal r...

Question

In an ideal refrigeration (reversed Carnot) cycle, the condenser and evaporator temperatures are 27°C and -13°C respectively. The COP of this cycle would be

A

15.0

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B

6.5

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C

7.5

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D

10.5

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Solution

The correct option is B 6.5
Given data
$T_{1} = 27^{\circ} C = (27 + 273) K = 300 K$
$T_{2} = - 13^{\circ} C = (- 13 + 273) K = 260 K$
$(C O P)_{R} = \frac{T_{2}}{T_{1} - T_{2}} = \frac{260}{300 - 260} = 6.5$

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