In an ideal transformer, the voltage and the current in primary coil are 200V and 2A respectively. If the voltage in the secondary coil is 200V, then the value of current in the secondary coil will be
A
0.2A
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B
2A
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C
10A
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D
20A
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Solution
The correct option is A0.2A As the transformer is ideal the power in both coils is conserved Pp=Ps VpIp=VsIs 200×2=2000×Is Is=0.2A