In an imaginary atmosphere, the air exerts a small force $F$ on any particle in the direction of the particle's motion. A particle of mass $m$ projected upwards takes a time $t_{1}$ in reaching the maximum height and $t_{2}$ in the return journey to the original point. Then:

t_{1} < t_{2}

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t_{1} > t_{2}

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t_{1} = t_{2}

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the relation between

t_{1}

and

t_{2}

depends on the mass of the particle

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Solution

The correct option is B $t_{1} > t_{2}$
here
$t_{1} =$ time for reaching maximum height.
$t_{2} =$ time for returning to the original point.
Due to the gravity, the downward velocity is greater than the upward velocity of mass $m$ . So, the upward motion will take more time than the downward motion.
i.e, $t_{1} > t_{2}$

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In an imaginary atmosphere, the air exerts a small force F on any particle in the direction of the particle's motion. A particle of mass m projected upwards takes a time t1 in reaching the maximum height and t2 in the return journey to the original point. Then:

The correct option is B t1>t2here t1= time for reaching maximum height.t2= time for returning to the original point.Due to the gravity, the downward velocity is greater than the upward velocity of mass m. So, the upward motion will take more time than the downward motion.i.e, t1>t2

In an imaginary atmosphere, the air exerts a small force $F$ on any particle in the direction of the particle's motion. A particle of mass $m$ projected upwards takes a time $t_{1}$ in reaching the maximum height and $t_{2}$ in the return journey to the original point. Then: