Question

In an insulated vessel, $250gm$ of ice at $0^{o}C$ is added to $500gm$ of water at ${20}^{o}C$ , what is the final temperature of the mixture and what is the final composition of the mixture?

Answer 1

Latent heat to ice to convert it into water then water to final temperature is equal to cooling of water of hot water to final temperature

Amount of Heat lost is equal to heat gained

Specific heat capacity of water is$$1cal/kg$$

$0.250\times 20+0.250\times \left(T\right)\times 1=0.5\times \left(20-T\right)\times 1$

$5+0.250T=1-0.5T$

$4=0.250T$

Hence the temperature is ${16}^{\circ }$ and mixture is water.