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Fringe Width in YDSE

In an interfe...

Question

In an interference experiment, intensity ratio at the bright to dark fringe is $9 : 1$ . Amplitudes of interfering waves was in the ratio.

A

3 : 1

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B

9 : 1

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C

2 : 1

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D

4 : 1

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Solution

The correct option is B $2 : 1$
$\frac{I_{m a x}}{I_{m i n}} = 9 = \frac{(a_{1} + a_{2})^{2}}{(a_{1} - a)^{2}}$
possible solution is $a_{2} = 2 A$ and $a_{1} = A$

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