In an interference experiment- the ratio of amplitudes of coherent waves is a1a2 - 13- The ratio of maximum and minimum intensities of fringes will be

Given a_1a_2 = 13 Ratio of intensities, I_1I_2 = (a_1a_2 )^2 = 19 Now, I_maxI_min = (√(I_1) + √(I_2)√(I_1) √(I_2) )^2 = (1 + 31 3 )^2 = 4. nbsp; ...

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Mathematics

Probability

In an interfe...

Question

In an interference experiment, the ratio of amplitudes of coherent waves is $\frac{a_{1}}{a_{2}} = \frac{1}{3}$ . The ratio of maximum and minimum intensities of fringes will be

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Solution

The correct option is A $4$
Given $\frac{a_{1}}{a_{2}} = \frac{1}{3}$
Ratio of intensities, $\frac{I_{1}}{I_{2}} = {(\frac{a_{1}}{a_{2}})}^{2} = \frac{1}{9}$
Now, $\frac{I_{m a x}}{I_{m i n}} = {(\frac{\sqrt{I_{1}} + \sqrt{I_{2}}}{\sqrt{I_{1}} - \sqrt{I_{2}}})}^{2} = {(\frac{1 + 3}{1 - 3})}^{2} = 4$ .

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In an interference experiment, the ratio of amplitudes of coherent waves is a1a2=13. The ratio of maximum and minimum intensities of fringes will be

The correct option is A 4Given a1a2=13 Ratio of intensities, I1I2=(a1a2)2=19 Now, ImaxImin=(√I1+√I2√I1−√I2)2=(1+31−3)2=4.

In an interference experiment, the ratio of amplitudes of coherent waves is $\frac{a_{1}}{a_{2}} = \frac{1}{3}$ . The ratio of maximum and minimum intensities of fringes will be