MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

YDSE Problems II

In an interfe...

Question

In an interference pattern the $(n + 4)^{t h}$ blue bright fringe and $n^{t h}$ red bright fringe are formed at the same spot. If red and blue light have the wavelength of $7800 Å$ and $5200 Å$ , then value of $n$ should be :

Open in App

Solution

Fringes are formed at same spot means fringes coincide
$n_{1} λ_{1} = n_{2} λ_{2}$
$(n + 4) 5200 Å = (n) 7800 Å$
$(n + 4) 4 = 6 n$
$n = 8$

Suggest Corrections

thumbs-up

8

Similar questions

Q. A biprism experiment was performed by using red light of wavelength

6500 ˚ A

and blue light of wavelength

5200 ˚ A

. the value of n for which

(n + 1)^{t h}

blue bright band coincides with

n^{t h}

Q. In Young's double slit experiment using yellow and blue lights of wavelengths

560 nm

420 nm

respectively, the value of

n

n^{t h}

order of yellow bright fringe coincides with

(n + 1)^{t h}

order of blue bright fringe is

Q. In Young's experiment, the wavelength of red light is

7800 ˚ A

and that of blue light is

5200 ˚ A

n

(n + 1)

th blue band coincides with

n

Q. In Young's double slit experiment, the wavelength of red light

7500 \circ A

and that of blue light is

5000 \circ A

n

n^{t h}

bright band due to red light coincides with

(n + 1)^{t h}

bright band due to blue light, is

Q. In Young's double slit experiment, the wavelength of red light is

7800 ˚ A

and that of blue is

5200 ˚ A .

n

n^{t h}

bright band due to red light coincides with

(n + 1)^{t h}

bright band due to blue light is-

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

YDSE Problems

PHYSICS

Watch in App

explore_more_icon

Explore more

YDSE Problems II

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon