Question

In an intrinsic semiconductor band gap is $1.2eV$ then ratio of number of charge carriers at $600K$ and $300K$ is of order:

• A. ${10}^4$
• B. ${10}^7$
• C. ${10}^{10}$
• D. ${10}^3$

Answer 1

The correct option is C ${10}^{10}$

The ratio is given by the formula:

$\frac{n_1}{n_2}=\frac{e^{-\frac{E_g}{k{T}_1}}}{e^{-\frac{E_g}{k{T}_2}}}=\frac{{8.5\times 10}^{-11}}{7.224\times {10}^{-21}}=1.176\times {10}^{10}$