In an ionic solid r(+) = 1.6 and r(-) = 1.864 . Use the radius ratio rule to determine the edge length of the cubic unit cell in .

4

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2 \sqrt{3}

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3 \sqrt{3}

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4 / \sqrt{3}

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Solution

The correct option is A $4$
$r_{+} = 1.6$ $r^{-} = 1.864$
Along the body diagonal $2 (r_{+} + r_{-}) = a \sqrt{3}$
$2 (1.6 + 1.864) = a \sqrt{3}$
$\Rightarrow a = 4$

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