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Question

In an irreversible process taking place at constant T and P and in which only PV work is being done, the change in free energy (dG) and change in entropy (dS) satisfy the criteria:


A

(dS)V,U=0,(dG)T,P = 0

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B

(dS)V,U=0,(dG)T,P = +ve

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C

(dS)V,U=ve,(dG)T,P = -ve

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D

(dS)V,U=+ve,(dG)T,P = -ve

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Solution

The correct option is D

(dS)V,U=+ve,(dG)T,P = -ve


ΔG=ΔHTΔS
Since T is constant, DeltaH=0
Also, as the process is spontaneous, we can conclude from the above equation that:
G = -ve
S = +ve


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