Question

In an irrigated field, the net irrigation requirement is 15 cm, the application efficiency is 80% and water conveyance efficiency is 60%. What is the gross irrigation requirement (in cm)?

• A. 11.25
• B. 18.75
• C. 25
• D. 31.25

Answer 1

The correct option is D 31.25

$\text{Net Irrigation Requirement}\left(NIR\right)=15\text{cm}$
$\text{Water Application Efficiency}\left(n_a\right)=80\%=0.80$
$\text{Water Conveyance Efficiency}\left(n_C\right)=60\%=0.60$
To calculate: Gross irrigation Requirement (GIR)
As we know that,
$GIR=\frac{FIR}{n_c}=\frac{NIR}{n_a.n_c}$
$\text{where,}FIR=\text{Field Irrigation Requirement}$
$\therefore GIR=\frac{15\text{cm}}{0.8\times 0.6}$
$GIR=31.25\text{cm}$