Question

In an isobaric process, $\Delta Q=\frac{K\gamma }{\gamma -1}$ where $\gamma =C_p/C_v$. What is $K$?

• A. Pressure
• B. Volume
• C. $\Delta U$
• D. $\Delta W$

Answer 1

Answer: (D)

$\Delta W$

For constant pressure,$\Delta Q=n{C}_p\Delta T=n\left(\gamma C_v\right)\Delta T$

Also, work done=$\Delta W=p\Delta V=nR\Delta T=\Delta Q-\Delta U=(\gamma -1)n{C}_v\Delta T=\frac{\gamma -1}{\gamma }\Delta Q\Rightarrow \Delta Q=\frac{\gamma }{\gamma -1}\Delta W$

Thus, $K=\Delta W$