Question

In an isobaric process ratio of heat supplied to the system, to workdone by the system for diatomic gas is:

• A. 1:1
• B. 7:2
• C. 7:5
• D. 5:7

Answer 1

Answer: (B)

7:2

For isobaric process & $n=1mol$

$dQ=\frac{5}{2}RdT+RdT=\frac{7}{2}RdT$

$\&dw=RdT$

$Ratio\to \frac{dQ}{dw}=\frac{\frac{7}{2}RdT}{RdT}=7:2$

Hence the answer is (B)