Question

In an isobaric process, the ratio of heat supplied to the system $\Delta Q$ and work done by the system $\Delta W$ for diatomic gas is

• A. 1 : 1
• B. 7 : 2
• C. 7 : 5
• D. 5 : 7

Answer 1

The correct option is B 7 : 2

Heat supplied to the system is ($\Delta Q$) and work done by the system is $\Delta W$. Therefore, ratio will be
$\frac{\Delta Q}{\Delta W}=\frac{\Delta Q}{\Delta Q-\Delta E}$;
{$\Delta Q=\Delta W+\Delta E$; }
$=\frac{n{c}_{p}dT}{n{c}_{p}dT-n{c}_{v}dT}$$=\frac{c_p}{(c_p-c_v)}$ $=\frac{7R}{2R}=\frac{7}{2}$
{For diatomic of gas, $c_p=\frac{7R}{2}$and $c_v=\frac{5R}{2}$}