In an isobaric reversible process, the ratio of heat supplied to the system (dq) and work done by the system (dW) for a ideal monoatomic gas is:
A
52
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B
72
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C
32
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D
12
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Solution
The correct option is A52 At constant pressure, (isobaric process) heat supplied is given as: qp=nCpdT Cp for a monoatomic gas = 52R So, qp=52nRdT Work done by system is given as: dw=nRdT Hence, the ratio is: dqdw=(5/2)nRdTnRdT =52