In an isosceles ΔABC, AB = AC. If BC is parallel to y-axis, coordinates of vertex B and centroid of ΔABC are (–5, 2) and (–4, –2) respectively, then the coordinates of vertex A when –6 is ordinate of vertex C are
A
(2, 2)
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B
(2, -2)
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C
(-2, 2)
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D
(-2, -2)
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Solution
The correct option is D (-2, -2) Given that ΔABC is an isosceles triangle.
Therefore, AD is the perpendicular bisector as well as median of BC.
Since BC is parallel to y-axis, abscissa of vertex C in equal to abscissa of vertex B