Question

In an isosceles $\Delta$ABC, $\angle$A is 30${}^{\circ }$. The sides AB and AC are equal. Using constructions, find which side of $\Delta$ABC is the shortest.

• A. BC
• B. AC
• C. AB
• D. Data Insufficient

Answer 1

The correct option is A

BC

Since the measure of angle A = 30${}^{\circ }$, then it follows that the other two angles must be equal and add up to 150${}^{\circ }$. That means they are each 75${}^{\circ }$.

After construction, you can see that the side opposite to $\angle$A (side BC) is the smallest side.