In an Isosceles right angled $△ A B C$ its hypotenuse $A C = 8$ cm. Find the length of side $A B$ and side $B C$ .

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Solution

$△ A B C$ is isosceles right angled $△$
${A B}^{2} + {B C}^{2} = {A C}^{2}$
$x^{2} + x^{2} = 8^{2}$
$2 x^{2} = 64$
$x^{2} = 32$
$x = \sqrt{32} = 4 \sqrt{2} ㎝$
$∴ A B = B C = 4 \sqrt{2} ㎝$

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In an Isosceles right angled △ABC its hypotenuse AC=8 cm. Find the length of side AB and side BC.

△ABC is isosceles right angled △AB2+BC2=AC2x2+x2=822x2=64x2=32x=√32=4√2㎝∴AB=BC=4√2㎝

In an Isosceles right angled $△ A B C$ its hypotenuse $A C = 8$ cm. Find the length of side $A B$ and side $B C$ .

$△ A B C$ is isosceles right angled $△$
${A B}^{2} + {B C}^{2} = {A C}^{2}$
$x^{2} + x^{2} = 8^{2}$
$2 x^{2} = 64$
$x^{2} = 32$
$x = \sqrt{32} = 4 \sqrt{2} ㎝$
$∴ A B = B C = 4 \sqrt{2} ㎝$