In an isosceles ABC- AB-AC and - BAC-30- Find the remaining angles-

Given, ABC is isosceles with AB=AC. ⇒∠ ABC=∠ ACB=θ According to angle sum property, 30^∘+θ +θ =180^∘ ⇒θ = 75^∘ Hence, the remaining angles are: ∠ ABC=∠ ACB=75 ...

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Standard VIII

Mathematics

Angle Sum Property of a Triangle

In an isoscel...

Question

In an isosceles $△ A B C, A B = A C$ and $∠ B A C = 30^{\circ}$ . Find the remaining angles.

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Solution

Given, $△ A B C$ is isosceles with $A B = A C$ .
$\Rightarrow ∠ A B C = ∠ A C B = θ$

According to angle sum property,
$30^{\circ} + θ + θ = 180^{\circ}$
$\Rightarrow θ = 75^{\circ}$

Hence, the remaining angles are:
$∠ A B C = ∠ A C B = 75^{\circ}$

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In an isosceles △ABC, AB=AC and ∠BAC=30∘. Find the remaining angles.

Given, △ABC is isosceles with AB=AC. ⇒∠ABC=∠ACB=θ According to angle sum property, 30∘+θ+θ=180∘ ⇒θ=75∘ Hence, the remaining angles are: ∠ABC=∠ACB=75∘

In an isosceles $△ A B C, A B = A C$ and $∠ B A C = 30^{\circ}$ . Find the remaining angles.

Given, $△ A B C$ is isosceles with $A B = A C$ .
$\Rightarrow ∠ A B C = ∠ A C B = θ$

According to angle sum property,
$30^{\circ} + θ + θ = 180^{\circ}$
$\Rightarrow θ = 75^{\circ}$

Hence, the remaining angles are:
$∠ A B C = ∠ A C B = 75^{\circ}$