In an isosceles ∆ABC,
AB2 = 2AC2 (Given)
⇒ AB2 = AC2 + AC2
⇒ AB2 = AC2 + BC2 (AC = BC)
Using converse of Pythagoras theorem, we have
∆ABC is an isosceles right triangle right angled at C.
(In a triangle, if the square of one side is equal to the sum of the squares of other two sides, then the angle opposite to side is a right angle.)
∴ ∠C = 90º
In an isosceles triangle ABC, if AC = BC and AB2 = 2AC2, then ∠C = ___90º___.