In an isosceles triangle, if the third angle is greater than or equal to 80∘ then the maximum value each base angle can have is
A
100∘
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B
50∘
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C
40∘
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D
80∘
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Solution
The correct option is B50∘ Since our triangle is an isosceles triangle, its base angles will be equal. Let each base angle of the triangle be x∘. To acsertain the maximum value for x we should know the minimum value of the third angle. The minimum value for the third angle is 80∘.(Given) So using the angle sum propery: 80+x+x=180 80+2x=180 2x=180−80 2x=100 x=50∘