Question

In an isosceles triangle, Sum of two equal angles is ${36}^0$ more than twice the value of third angle. Find the linear equation of above condition along with slope of equation of straight line obtained.

• A. Slope$=2$
• B. Slope$=1$
• C. linear equation will be $y=x-18$, where $x$ is measure of identical angles and $y$ is third angle.
• D. linear equation will be $3y=2x+36$, where $x$ is measure of identical angles and $y$ is third angle.

Answer 1

Answer: (B), (C)

linear equation will be $y=x-18$, where $x$ is measure of identical angles and $y$ is third angle.

Let two identical angles measures $x$.
then their sum will be $\left(2x\right)$
And, Let third angle be $y$
Now according to question
$2x=36+2y$
On dividing $2$ both side we get
$\Rightarrow x=18+y\Rightarrow y=x-18$

This is the linear equation.
Also, On comparing with slope intercept form of line $y=mx+c$ where $m$ is slope of line and $c$ is y-intercept of line.
we get slope $=1$