Question

In an isosceles triangle, the vertex angle is ${50}^{\circ }$. What are the base angles of the triangle?

Answer 1

As we know that the base angle of an isosceles triangle are always equal and sum of interior angles of a triangle is $180°$.

Let the base angles of the isosceles triangle be $x°$ each.

$\therefore x+x+50°=180°$

$\Rightarrow 2x=180°-50°$

$\Rightarrow x=\frac{130°}{2}=65°$

Hence the base angles will be of $65°$ each.