Question

In an isothermal process if heat is released from an ideal gas then,

• A. Internal energy of the gas will measure
• B. Gas will do positive work.
• C. Gas will do negative work.
• D. The given process is not possible.

Answer 1

The correct option is C Gas will do negative work.

As the process is isothermal, $\Delta U=0$
Moreover, as heat is released by the gas, $\Delta Q<0$
Now, $\Delta Q=\Delta U+\Delta W$
$\Rightarrow \Delta Q=\Delta W$
$\therefore \Delta W<0$