In an L−C−R circuit the capacitance is changed from C to 4C. For the same resonant frequency, the inductance should be changed from L to
A
L/4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
L/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A L/4 ω=1√LC For, ω=constant→√LC=constant Therefore, C is inversely proportional to L So, if C is made 4C then L should be reduced to L/4 to keep ω constant.