Question

In an L-C-R series circuit, $R=\sqrt{5}\Omega ,X_L=9\Omega ,X_C=7\Omega$. If applied voltage in the circuit is 50V then impedance of the circuit in ohm will be

• A. $2$
• B. $3$
• C. $2\sqrt{5}$
• D. $3\sqrt{5}$

Answer 1

The correct option is B $3$

Impedance = $\sqrt{R^2+(X_L-X_C{)}^2}$

$=\sqrt{5+(9-7{)}^2}$

$=\sqrt{5+(2{)}^2}$

$=\sqrt{5+4}$

$=\sqrt{9}$

$=3\Omega$