Question

In an L-R circuit reactance and resistance are equal , the phase by which the voltage differ the
current is
(a) π/2 rad
(b) π/4 rad
(c) π rad
(d) 2 π rad

Answer 1

$$\begin{gathered} DearStudent, \\ ForanL-Rcircuit, \\ \tan \varphi =\frac{X_L}{R} \\ \varphi \to Phaseanglebetweenvoltageandcurrent. \\ {X}_L\to Inductivereac\tan ce. \\ R\to Resis\tan ce \\ Given, \\ {X}_L=R \\ \Rightarrow \\ \tan \varphi =\frac{X_L}{R}=\frac{X_L}{X_L}=1 \\ \Rightarrow \\ \varphi ={\tan }^{-1}\left(1\right)=\frac{\mathbf{\pi }}{\mathbf{4}}\mathit{r}\mathit{a}\mathit{d}\mathbf{,}\mathbf{}\mathit{o}\mathit{p}\mathit{t}\mathit{i}\mathit{o}\mathit{n}\mathbf{}\mathit{b} \\ Regards \end{gathered}$$