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Question

In an LC circuit, L=40 mH and C=100μF. If a voltage V(t)=10sin(314t) is applied across the circuit, the current flowing through it is given as:

A
0.52 cos 314 t
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B
10 cos 314 t
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C
5.2 cos 314 t
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D
0.52 sin 314 t
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Solution

The correct option is A 0.52 cos 314 t
Given, Inductance, L=40 mH
Capacitance, C=100 μF
impedance, Z=XCXL

Z=1ωCωL (Xc=1ωC and XL=ωL)

=1314×100×106314×40×103

=19.28 Ω

For capacitive circuit, current leads the voltage by π2, so

Current, i=V0Zsin(ωt+π/2)
i=1019.28cosωt=0.52cos(314 t)

Hence, (A) is the correct answer.

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