In an LCR circuit as shown below both switches are open initially. Now switch S1 is closed, S2 kept open. (q is charge on the capacitor and τ=RC is capacitive time constant). Which of the following statement is correct?
A
At t=2τ,q=CV(1−e−2)
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B
Work done by the battery is half of the energy dissipated in the resistor
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C
At t=τ,q=CV2
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D
At t=τ2,q=CV(1−e−1)
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Solution
The correct option is A At t=2τ,q=CV(1−e−2) Charge on capacitor at time t is q=CV(1−e−t/τ)
At t=2τq=CV(1−e−2)