In an LCR circuit L-8-0 henry-C-0-5 - F and R-100 ohm are in series- The resonsanance angular frequency is

The correct option is A 500 rad/s Resonance frequency = 1 √(LC) #10; #10; #160; #160; #160; #160; #160; #160; #160; #160; #160; ...

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Impedance in RLC Circuit

In an LCR c...

Question

In an $L C R$ circuit $L = 8.0 h e n r y, C = 0.5 μ F$ and $R = 100 o h m$ are in series. The resonsanance angular frequency is

500 r a d / s

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600 r a d / s

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700 r a d / s

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1000 r a d / s

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Solution

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= 8

= 0.5 μ F

R = 100 Ω

C = 0.5 μ F

0.5 μ F

100 Ω

L = 8.0 H, C - 0.5 μ F

R = 100 Ω

100 v o l t

A C

500 r a d / s

L C R

L = 0.8 H

C = 5 μ F

R = 10 Ω

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